[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] question on default namespace
-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 Hi, I tried to transform a document with a default namespace. In the result I wanted to include the contents of another document that is in no namespace. The xslt-snippet below didn't work, only when I deleted the xpath-default-namespace and added to all elements processed the namespace it worked. Are there any other solutions that include the xpath-default-namespace? XSLT extract: <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:tei="http://www.tei-c.org/ns/1.0" xpath-default-namespace="http://www.tei-c.org/ns/1.0" exclude-result-prefixes="tei"> [...some templates here...] <xsl:for-each select="document('http://diglib.hab.de/mss/10-aug-4f/facsimile.xml')//facsimile"> <xsl:copy-of select="."/> </xsl:for-each> Neither does this work, nor any <xsl:apply-templates> nor the immediate <xsl:copy-of select="document('...')//facsimile"/> Can I "reset" an xpath to no use of a namespace? Best, Torsten - -- Torsten Schassan Herzog August Bibliothek, Postfach 1364, D-38299 Wolfenbuettel Tel.: +49-5331-808-130, schassan {at} hab.de http://www.hab.de; http://www.hab.de/forschung/projekte/weiss64.htm -----BEGIN PGP SIGNATURE----- Version: GnuPG v1.4.7 (MingW32) Comment: Using GnuPG with Mozilla - http://enigmail.mozdev.org iD8DBQFJtRVAq4nZEP2KS4QRAjh1AJ9jCJYn3DzSD4Nb+36kOnr7IW+E8QCbBveR vnTvcx9XKgdVZ8S4zxmEOCU= =rwuj -----END PGP SIGNATURE-----
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