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Re: most efficient way to get XML source's parent dir
Subject: Re: most efficient way to get XML source's parent dir path
From: Robert Koberg <rob@xxxxxxxxxx>
Date: Wed, 11 Feb 2009 11:23:17 -0500
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On Feb 11, 2009, at 11:02 AM, Michael Kay wrote:
Well, I tried to simplify the example. In reality, I am using
the unparsed-text function which has no base-uri argument ()
and the resolver is provided with a full java.net.URI so I
needed a way to create the correct path in the XPath. I
should have been more clear.
Am I still missing something?
You should definitely be using functions like base-uri() and resolve-
uri()
rather than trying to manipulate the URI "by hand".
OK - Owen, thanks for questioning what I was doing. And thanks to both
you and Mike for showing me the correct way to deal with it.
best,
-Rob
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