Cart
|
[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Categorise Node by Unique Attribute
 I want to group nodes in an XML file, placing a heading above each category. The category is defined in an attribute which may be the same for a series of records. The code sample below shows what I want to do. I've been going round in circles trying combinations of variables, templates, for-each loops and I just can't seem to get a handle on the problem. Any help would be very gratefully received. Here is an XSLT 1.0 stylesheet that uses Muenchian grouping: <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:output method="html" indent="yes"/> <xsl:key name="cat"
match="book"
use="concat(parent::author/@name, '|', @genre)"/> <xsl:template match="/">
<html lang="en">
<head>
<title>Books</title>
</head>
<body>
<h1>Books</h1>
<xsl:apply-templates select="authors/author"/>
</body>
</html>
</xsl:template><xsl:template match="author"> <h2> <xsl:value-of select="@name"/> </h2> <xsl:apply-templates select="book[generate-id() = generate-id(key('cat', concat(parent::author/@name, '|', @genre))[1])]" mode="group"/> </xsl:template> <xsl:template match="book" mode="group"> <h3> <xsl:value-of select="@genre"/> </h3> <ul> <xsl:apply-templates select="key('cat', concat(parent::author/@name, '|', @genre))"/> </ul> </xsl:template> <xsl:template match="book">
<li>
<xsl:value-of select="@name"/>
</li>
</xsl:template></xsl:stylesheet> Read more about that on http://www.jenitennison.com/xslt/grouping/index.xml -- Martin Honnen http://JavaScript.FAQTs.com/ 
|
PURCHASE STYLUS STUDIO ONLINE TODAY!Purchasing Stylus Studio from our online shop is Easy, Secure and Value Priced! 
Download The World's Best XML IDE!Accelerate XML development with our award-winning XML IDE - Download a free trial today! Subscribe in XML format
|
