Re: xsl:for-each-group and identity transform

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Subject: Re: xsl:for-each-group and identity transform
From: Owen Rees <owen.rees@xxxxxx>
Date: Fri, 23 Jan 2009 15:14:19 +0000

--On 23 January 2009 15:07 +0100 Jesper Tverskov wrote:

But this (my) template works:

<xsl:template match="element()|comment()|processing-instruction()"
mode="group"> <xsl:copy-of select="current-group()"/>
</xsl:template>

Change it to:

<xsl:template match="element()|comment()|processing-instruction()" mode="group"> <xsl:apply-templates select="current-group()"/> </xsl:template>

Don't forget to add the default mode identity template and whatever other default mode templates you need to adjust the non-h elements.

--
Owen Rees; speaking personally, and not on behalf of HP.
========================================================
Hewlett-Packard Limited.   Registered No: 690597 England
Registered Office:  Cain Road, Bracknell, Berks RG12 1HN

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Re: xsl:for-each-group and identity transform, (continued)

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Re: xsl:for-each-group and id, David Carlisle	Thread	Re: xsl:for-each-group and id, Jesper Tverskov
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