[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: multiple files to single file problem
> <xsl:template match="/" name="main"> > <xsl:element name="cover-body"> It's so much clearer if you use literal result elements: <cover-body> instead of <xsl:element name="cover-body">. > <xsl:for-each select="for $x in > collection('file:///D:/cover/sample > xmls/pageall/else/nima?select=*.xml;recurse=yes;on-error=ignore') > return $x"> The XPath expression "for $x in EXPR return $x" can always be rewritten "EXPR". You just want <xsl:for-each select="collection(....)"> > <xsl:variable name="a" > select="document(document-uri(/))"/> That's equivalent to <xsl:variable name="a" select="."/> > <xsl:element name="author"> > > <xsl:value-of > select="$a/article/head/author-group/author/given-name"/> > <xsl:text/> > > <xsl:value-of select="$a/article/head/author-group/author/surname"/> > </xsl:element> > </xsl:element> xsl:value-of takes the selected nodes (all the given-names) and outputs their values, space-separated. So you have asked for all the given-names, space-separated, then all the surnames, space-separated. What you want is this: <author> <xsl:for-each select="$a/article/head/author-group/author"> <xsl:value-of select="given-name, surname"/> </xsl:for-each> </author> perhaps with some added punctuation or markup. Michael Kay http://www.saxonica.com/
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