[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Simple question? element value last() - element va
You want 1 number but you are looping over <xsl:for-each select="works_details"> and working out a number for each. As each works_details only has a single "Work_Year child Work_Year[last()] and Work_Year[1] are the same element, so you get 0 in each case for the difference. You want <xsl:template match="artist_works"> <xsl:value-of select=" (works_details/Work_Year)[last()] - (works_details/Work_Year)[1]"/> </xsl:template> David ________________________________________________________________________ The Numerical Algorithms Group Ltd is a company registered in England and Wales with company number 1249803. The registered office is: Wilkinson House, Jordan Hill Road, Oxford OX2 8DR, United Kingdom. This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. ________________________________________________________________________
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