Re: What is $p in the definition of fn:subsequence ?

An additional question:

  The spec doesn't specify the desired behavior if $length is <=  0.

Should the function return the empty sequence, a reversed subsequence
(if $length is < 0) or should an error be raised? The same question
goes for fn:substring().


-- 
Cheers,
Dimitre Novatchev
---------------------------------------
Truly great madness cannot be achieved without significant intelligence.
---------------------------------------
To invent, you need a good imagination and a pile of junk
-------------------------------------
Never fight an inanimate object
-------------------------------------
You've achieved success in your field when you don't know whether what
you're doing is work or play


On Fri, Jul 4, 2008 at 8:16 PM, Dimitre Novatchev <dnovatchev@xxxxxxxxx> wrote:
> The definition of the fn:subsequence in the F & O   W3C  Recommendation at:
>
>    http://www.w3.org/TR/xpath-functions/#func-subsequence
>
> contains the following text:
>
> "Summary: Returns the contiguous sequence of items in the value of
> $sourceSeq beginning at the position indicated by the value of
> $startingLoc and continuing for the number of items indicated by the
> value of $length.
>
> In the two-argument case, returns:
>
> $sourceSeq[fn:round($startingLoc) le $p]
> In the three-argument case, returns:
>
> $sourceSeq[fn:round($startingLoc) le $p
>     and $p lt fn:round($startingLoc) + fn:round($length)]"
>
>
> There is no definition of $p and this definitely seems to be a bug in
> the document.
>
> Could somebody, please, confirm what is meant by "$p" in this text?
>
> --
> Cheers,
> Dimitre Novatchev
> ---------------------------------------
> Truly great madness cannot be achieved without significant intelligence.
> ---------------------------------------
> To invent, you need a good imagination and a pile of junk
> -------------------------------------
> Never fight an inanimate object
> -------------------------------------
> You've achieved success in your field when you don't know whether what
> you're doing is work or play