Re: Nesting XPath predicates

Liam Quin wrote:

  Hi

> > //service[@name = current()/serviceName]

> That will work in the given example, but stops working if
> you put that line inside a for-each...  or more precisely
> works differently :-)

  Yes.  It will "work differently," exactly the same way your variable
will "work differently" if you put it in a for-each ;-)

  Regards,

--drkm























__________________________________________________
Do You Yahoo!?
En finir avec le spam? Yahoo! Mail vous offre la meilleure protection possible contre les messages non sollicitis 
http://mail.yahoo.fr Yahoo! Mail