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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: How to sort a nodeset returned by key()?
 It looks like XML tags in my posts have been filtered by hotmail, so
I'm reposting.
2008/4/5, Dolmen ! <dolmen@xxxxxxxxxxx>:
>
> Hi,
>
> Short:
> How can i sort a nodeset returned by key(), store it in a variable,
> and still be able to compare its nodes with nodes of the original
> document ?
>
> Long:
>
> This is a transformation of my data set to an HTML table using rowspans.
> I'm sorting my data, then I'm using a Muenchian grouping to group rows.
>
> My problem is that the order of my sorted node set is not the same as
> the order of the nodeset returned by key(). I have not found how to
> reliably distinguish the first node of the group to output the
> grouping cells in the right place.
>
> I'm using xsltproc (from libxslt)
>
> Here is an example using Steve Muench's data from
> http://www.dpawson.co.uk/xsl/sect2/N7450.html#d11343e31
>
> If I remove this sort, the XHTML, is clean, but the table is not sorted.
>
<demo>
<salesman id="0001" name="Rick Peterson">
<account id="act001" region="Midwest">Johnosn's Laundry</account>
<account id="act002" region="Canada">Franks's Laundry</account>
<account id="act003" region="Alaska">Mary's Laundry</account>
<account id="act004" region="New Jersey">Bill's Laundry</account>
<account id="act005" region="Midwest">Hammond's Laundry</account>
</salesman>
<salesman id="0003" name="Ty Coon">
<account id="act006" region="Canada">Franks's Diner</account>
<account id="act007" region="Midwest">Johnosn's Diner</account>
<account id="act008" region="Canada">Hammond's Diner</account>
<account id="act009" region="Alaska">Mary's Diner</account>
<account id="act010" region="Alaska">Bill's Diner</account>
</salesman>
</demo>
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes" encoding="UTF-8"
doctype-public="-//W3C//DTD XHTML 1.0 Strict//EN"
doctype-system="http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"
omit-xml-declaration="yes" />
<xsl:strip-space elements="*"/>
<!--
The output is completely broken as the result of key() is not in
the same order as the for-each node set.
-->
<xsl:key name="accounts-by-region" match="/demo/salesman/account"
use="@region"/>
<xsl:template match="/demo">
<html>
<head><title>Accounts ordered by region</title></head>
<body>
<table border="1" valign="top">
<tr><th>Region</th><th>Account</th></tr>
<xsl:for-each select="salesman/account">
<xsl:sort select="@region"/>
<xsl:sort select="."/>
<xsl:variable name="brand-model" select="concat(brand, '
', model)"/>
<tr>
<xsl:if test="count(. | key('accounts-by-region',
@region)[1]) = 1">
<td><xsl:attribute name="rowspan"><xsl:value-of
select="count(key('accounts-by-region',
@region))"/></xsl:attribute><xsl:value-of select="@region"/></td>
</xsl:if>
<td><xsl:value-of select="."/></td>
</tr>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
Olivier Mengui.
http://o.mengue.free.fr/
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