[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: Help with XPath statement
Thank you very much. It works perfectly. Raymond -----Original Message----- From: Florent Georges [mailto:lists@xxxxxxxxxxxx] Sent: Sunday, March 02, 2008 6:36 PM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: Re: Help with XPath statement Raymond Bissonnette wrote: > I'm stuck with XSLT 1.0 (ASP.NET) and worse, what I'm after is > to get a list of <set ... > nodes with the SelectNodes method > of an XmlDocument. I don't know XmlDocument. If you want XSLT, change <xsl:value-of select="."/> by <xsl:copy-of select=".."/> in the solution Ken proposed to you. If you want an XPath: section[@id = '0802']/set[ not(@key = ../following-sibling::section/set/@key) ] | section[@id = '0803']/set or: section[@id = '0802']/set[ not(@key = ../../section[@id = '0803']/set/@key) ] | section[@id = '0803']/set should be what you are after. Not tested! Regards, --drkm ____________________________________________________________________________ _ Ne gardez plus qu'une seule adresse mail ! Copiez vos mails vers Yahoo! Mail http://mail.yahoo.fr
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