[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: [XSLT] Put element in new-line
On 06/03/2008, igutierrez027@xxxxxxxxxxxxx <igutierrez027@xxxxxxxxxxxxx> wrote: > Hello everybody! > > How I can do for put <xs:schema ....> in his next new-line and also > <xs:element name="newFile" type="xs:string"/> in his next new-line? > > > <?xml version="1.0" encoding="UTF-8><xs:schema > xmlns:xs="http://www.w3.org/2001/XMLSchema" > xmlns:dc="http://purl.org/dc/elements/1.1/" > xmlns:ns1="http://bibtexml.sf.net/" elementFormDefault="qualified" > targetNamespace="http://bibtexml.sf.net/" version="2.0"> > > <xs:import namespace="http://purl.org/dc/elements/1.1/" > schemaLocation="dc.xsd"/> > <xs:element name="dateofread" type="xs:date"/> > <xs:element name="reviewed" type="xs:string"/><xs:element > name="newFile" type="xs:string"/> > > </xs:schema> I think you are after: <xsl:output indent="yes"/> used with at least: <xsl:template match="/"> <xsl:copy-of select="."/> </xsl:template> By the way your XML declaration is: <?xml version="1.0" encoding="UTF-8> when it should end with: ....encoding="UTF-8"?> you get some funny error message without that quote and question mark :) -- Andrew Welch http://andrewjwelch.com Kernow: http://kernowforsaxon.sf.net/
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