[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: xalan and replace "regex"
Matthew, I have checked this and when it nothing worked for me, I
decided to post to this list.
A simple sheet to test how would replace work : <?xml version="1.0" encoding="UTF-8" ?> <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xalan="http://xml.apache.org/xalan" xmlns:str="http://exslt.org/strings"> <xsl:import href="str/str.xsl" /> <xsl:template match="program"> <xsl:call-template name="str:replace"> <xsl:with-param name="string" select="." /> <xsl:with-param name="search" select="public" /> <xsl:with-param name="replace" select="object" /> </xsl:call-template> </xsl:template> </xsl:stylesheet> This did not help and nothing changed in the output. This is why I am considering another solution. Matthew L. Avizinis wrote: Matthew L. Avizinis wrote:
|
PURCHASE STYLUS STUDIO ONLINE TODAY!Purchasing Stylus Studio from our online shop is Easy, Secure and Value Priced! Download The World's Best XML IDE!Accelerate XML development with our award-winning XML IDE - Download a free trial today! Subscribe in XML format
|