[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: xalan and replace "regex"
also check out: http://xml.apache.org/xalan-j/extensionslib.html#exslt http://www.exslt.org for examples Mansour wrote: > Hello: > Is there any way I can use replace with xalan. I have tried every > thing possible but couldn't get it to work: > > <?xml version="1.0" encoding="UTF-8" ?> > <xsl:stylesheet version="2.0" > xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > xmlns:xalan="http://xml.apache.org/xalan" > xmlns:str="http://exslt.org/strings"> > <xsl:import href="str/str.xsl" /> > <xsl:template match="program"> > <xsl:value-of select="replace(.,'public','<KeyWord> pulic > </KeyWord>')" /> > </xsl:template> > </xsl:stylesheet> > > > > > I need to scan a piece of java code and be able to highlight the words > based on their meaning. Anyone had luck with xalan regex ?? or > analyze-string ??
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