[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: Generate a List
I'm guessing that you want something like this: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="html"/> <xsl:template match="head"> <h1> <xsl:apply-templates/> </h1> </xsl:template> <xsl:template match="list"> <ul> <xsl:apply-templates/> </ul> </xsl:template> <xsl:template match="item"> <li> <xsl:apply-templates/> </li> </xsl:template> </xsl:stylesheet> <xsl:value-of select="child::item"/> in your "list" template will only give you the text values of those child nodes. You were missing the HTML structure. Also, you can omit the <xsl:value-of/> here; the built-in template for text nodes is to select the value of the node. Just <xsl:apply-templates/> inside an HTML element in your template. ~ Scott -----Original Message----- From: Alice Ju-Hsuan Wei [mailto:ajwei@xxxxxxxxxxx] Sent: Tuesday, November 06, 2007 5:57 PM To: xsl-list Subject: Generate a List Hi, I am trying to use the XSLT to generate something simple like a list and output it to HTML with <ul> and <li> tags. This is my XSLT: <xsl:template match="head"> <p> <xsl:apply-templates/> </p> </xsl:template> <xsl:template match="list"> <xsl:value-of select="child::item"/> </xsl:template> My XML: <head>Things to do</head> <list> <item>Wash the dog</item> <item>Take out the trash</item> <item>Check out books on XSLT</item> <item>Go to the bank</item> <item>Pay bills</item> </list> Output: <p class="">Things to do</p> Wash the dog Take out the trash Check out books on XSLT Go to the bank Pay bills <br> Can anyone please tell me what is wrong with my code? Thanks to those who can help. Alice
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