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Re: [XSL] id() in Ancestor Nodes?
Subject: Re: [XSL] id() in Ancestor Nodes?
From: George Cristian Bina <george@xxxxxxxxxxxxx>
Date: Thu, 04 Oct 2007 10:12:38 +0300
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Two more points in addition to Ken's reply.
You can also use a Schema aware XSLT 2.0 processor like Saxon8 SA with
an XML schema that specifies as xs:ID the ID values and you will get the
id function working.
The alternative to id is to define and use a key. For instance you can
define
<xsl:key name="publicationById" match="publication" use="@xml:id"/>
and replace
id('@publish') (which should have been id(@publish) BTW) with
key('publicationById', @publish)
Best Regards,
George
---------------------------------------------------------------------
George Cristian Bina - http://aboutxml.blogspot.com/
<oXygen/> XML Editor, Schema Editor and XSLT Editor/Debugger
http://www.oxygenxml.com
G. Ken Holman wrote:
At 2007-10-03 23:28 -0400, Alice Ju-Hsuan Wei wrote:
I am trying to use the id function in XSLT to extract the
publication id information from the "attribute" and have the output
display the name of the publisher itself as it is. The complete code
is as follows:
XML:
<bookshelf>
I note there is no DTD declaration of the attribute that has the ID type
... therefore, if you are using XSLT 1.0 you will need:
<!DOCTYPE bookshelf
[
<!ATTLIST publication xml:id ID #IMPLIED>
]>
<bookshelf>
If you are using XSLT 2.0, it is up to your XSLT processor to choose to
implicitly support xml:id (ref: 3.11 note), and if it does not, the
above is required.
I tried using the id function:
<xsl:template name="bookpublisher">
<xsl:variable name="name" select="id('@publish')"/>
If the processor is not instructed which attributes of which elements
have attributes of type ID (the name is irrelevant; the type is given in
a DTD declaration) for a given document, then the id() table is empty
for the document.
I hope this helps.
. . . . . . . . . . . . . Ken
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G. Ken Holman mailto:gkholman@xxxxxxxxxxxxxxxxxxxx
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