[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: Output input_xml apart from one tag change?
<xsl:copy>.....</xsl:copy> does a shallow copy of the current node. Think of it as copying the element tags, and then invoking the nested instructions to create the element content (that's not really what happens, there aren't any tags in the tree, but it's a first-order approximation). <xsl:copy-of select="@*"/> says copy the attributes of the current element unchanged <xsl:apply-templates/> says process each child of the current element using its appropriate template rule. That's either the generic identity template (invoked recursively), or the special template for the one element you want to change. Michael Kay http://www.saxonica.com/ > does xsl:copy copy all the descendants of the current node? > > If yes, then it will copy the node which was intended to > change through some template, right? > > If no, then how do the descendants of the current node get copied? > > Thanks, > J > > On 10/2/07, Martin Honnen <Martin.Honnen@xxxxxx> wrote: > > John Smith wrote: > > > That works perfectly, thanks. But what actually happens here: > > > > > > <xsl:copy><xsl:copy-of > > > select="@*"/><xsl:apply-templates/></xsl:copy> > > > > xsl:copy copies the current node. xsl:copy-of select="@*" > copies any > > attribute nodes. xsl:apply-templates processes all child nodes. > > > > -- > > > > Martin Honnen > > http://JavaScript.FAQTs.com/
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