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Re: Finding the current node type

Subject: Re: Finding the current node type
From: Kamal Bhatt <kbhatt@xxxxxxxxx>
Date: Tue, 31 Jul 2007 08:55:27 +1000
Re:  Finding the current node type
If I understand what you are trying to do, you could use local-name(). This will give you the name of the node.


Mark Anderson wrote:
Hi All

I'm trying to figure out a way to determine the "type" of the current
node in an nodeset.

I have a union of two dissimilar nodesets and I need to number the
combined set sequentially in my output. I also need to output details
from each node, but as they are completely different I need to process
each node type differently based on it's contents.

Here's a silly example

<products>
	<speaker>
		<woofer>12 inch</woofer>
		<rms_power>70 watts</rms_power>
		<peak_power>95 watts</peak_power>
		<height>40 inches</height>
		<width>18 inches</width>
		<depth>18 inches</depth>
	</speaker>
	<laptop>
		<disk>80GB</disk>
		<screen>15 inch</screen>
		<cpu>Intel Core Duo 2.3ghz</cpu>
		<weight>5.2lbs</weight>
	</laptop>
	...
</products>

So, I need to do something like:

<xsl:for-each select="speaker | laptop">
	<!-- Assign a sequential Number -->
	Item No: <xsl:value-of select="position()"/> <br />
	<!-- Now output item-specific details -->
	<xsl:choose>
		<xsl:when test="node = speaker">
			RMS Power: <xsl:value-of select="rms_power"/>
<br />
			Peak Power: <xsl:value-of select="peak_power"/>
<br />	
		</xsl:when>
		<xsl:when test="node = laptop">
			Disk Drive: <xsl:value-of select="disk"/> <br />
			CPU: <xsl:value-of select="cpu"/> <br />

</xsl:when>
</xsl:choose>
</xsl:for-each>


So, what I need to figure out is the test in the when clause to see
which type of node I'm processing.

I could hack it with something like:

<xsl:when test="count(rms_power) &gt; 0"> <!-- Must be a speaker -->
RMS Power: <xsl:value-of select="rms_power"/>
Peak Power: <xsl:value-of select="peak_power"/>
</xsl:when>


However, it's messy and I have to find unique child nodes for every
product.

I'm sure there's a more elegant way

Can anyone help?

TIA

Mark




--
Kamal Bhatt

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