Re: How to get element name for output

There is also local-name() if for some reason you want to do get the
name without a namespace prefix. I could be misunderstanding how
local-name() works compared to name(), but hopefully someone else can
clarify if I am wrong about that.

You can get the name of a node using the XPath name() function, for example

<attribute type="{name()}"/>

Michael Kay
http://www.saxonica.com/

> -----Original Message-----
> From: Chaudhary, Harsh [mailto:HCHAUDHA@xxxxxxxxx]
> Sent: 06 June 2007 22:33
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject:  How to get element name for output
>
> Hi,
>
> I am writing XSLt (ver 1.0) for output to an XML file. At one
> point I would like to get the name of the element and include
> that in the output. An example would be:
>
> Input XML:
>
> <rootElement>
>         <productAttributeList>
>             <attributeMap>
>                 <ReinstatementInProc>N</ReinstatementInProc>
>             </attributeMap>
>             <elementName>attribute</elementName>
>         </productAttributeList>
> </rootElement>
>
> Output XML:
>
> <rootElement>
>     <attribute type="ReinstatementInProc">N</attribute>
> </rootElement>
>
> I would really appreciate your help on this.
>
> Thanks,
> Harsh.