[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] org.apache.xpath.objects.XRTreeFrag error
Hi everybody, I'm trying to use the XSL code bellow with Xalan 2.5.2 and I'm getting the error described at http://www.biglist.com/lists/xsl-list/archives/200505/msg00391.html. The XRTreeFrag error is on line "". As you can see, I can't avoid to use a tree fragment. Did anyone have this problem? How can I solve it? <xsl:template name="check_identical"> <xsl:param name="comp1"/> <xsl:param name="comp2"/> <xsl:variable name="string1"> <xsl:call-template name="stringify"> <xsl:with-param name="node"> <xsl:copy-of select="$comp1"/> </xsl:with-param> </xsl:call-template> </xsl:variable> <xsl:variable name="string2"> <xsl:call-template name="stringify"> <xsl:with-param name="node"> <xsl:copy-of select="$comp2"/> </xsl:with-param> </xsl:call-template> </xsl:variable> <xsl:value-of select="$string1=$string2"/> </xsl:template> <xsl:template name="stringify"> <xsl:param name="node"/> <xsl:for-each select="$node/*/*"> <xsl:choose> <xsl:when test="boolean(local-name())">< <xsl:value-of select="local-name()"/> <xsl:variable name="pos" select="position()"/> <xsl:for-each select="@*"> <xsl:text> </xsl:text> <xsl:value-of select="local-name()"/>="<xsl:value-of select="."/>"</xsl:for-each> <xsl:call-template name="stringify"> <xsl:with-param name="node"> <xsl:copy-of select="."/> </xsl:with-param> </xsl:call-template></ <xsl:value-of select="local-name()"/>></xsl:when> <xsl:otherwise> <xsl:value-of select="normalize-space(.)"/> </xsl:otherwise> </xsl:choose> </xsl:for-each> </xsl:template> Thanks. Leopoldo Melo __________________________________________________ Fale com seus amigos de graga com o novo Yahoo! Messenger http://br.messenger.yahoo.com/
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