Re: XPath selecting chain of following siblings of the

At 2007-03-10 17:13 +0530, Mukul Gandhi wrote:
>I wonder, why this XSLT 1.0 solution doesn't work:

 From what I can tell it is because you only look at the "next" a and
not all contiguous a elements that follow:

> <xsl:apply-templates select="following-sibling::*[1][self::a]" />

Did you mean to do what is in the code below? This appears to work just fine.

I hope this helps.

. . . . . . . . . Ken

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">

<xsl:output method="xml" indent="yes"/>

<!--identity transform for all nodes other than 'a'-->
<xsl:template match="node() | @*">
  <xsl:copy>
    <xsl:apply-templates select="node() | @*" />
  </xsl:copy>
</xsl:template>

<!--the first a-->
<xsl:template match="a[not(preceding-sibling::*[1][self::a])]">
  <a-block>
    <xsl:apply-templates select="." mode="nested"/>
  </a-block>
</xsl:template>

<!--other a's when nested-->
<xsl:template match="a" mode="nested">
  <xsl:copy-of select="."/>
  <xsl:apply-templates select="following-sibling::*[1][self::a]"
                       mode="nested"/>
</xsl:template>

<!--other a's when not nested can be ignored-->
<xsl:template match="a"/>

</xsl:stylesheet>

--
World-wide corporate, govt. & user group XML, XSL and UBL training
RSS feeds:     publicly-available developer resources and training
G. Ken Holman                 mailto:gkholman@xxxxxxxxxxxxxxxxxxxx
Crane Softwrights Ltd.          http://www.CraneSoftwrights.com/s/
Box 266, Kars, Ontario CANADA K0A-2E0    +1(613)489-0999 (F:-0995)
Male Cancer Awareness Aug'05  http://www.CraneSoftwrights.com/s/bc
Legal business disclaimers:  http://www.CraneSoftwrights.com/legal

--
Regards,
Mukul Gandhi