RE: Re: xsl:analyze-string use clarification needed

Thanks. I've modified the expression to "^[A-Z]+", and I've got what I need.
--
Charles Knell
cknell@xxxxxxxxxx - email

-----Original Message-----
From:     Andrew Welch <andrew.j.welch@xxxxxxxxx>
Sent:     Tue, 23 Jan 2007 14:58:32 +0000
To:       xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject:  Re:  xsl:analyze-string use clarification needed

I'm having a problem understanding xsl:analyze-string, or perhaps the problem is with my regex.

I'm working with a VARCHAR2 column in an Oracle database. This column has been "re-purposed" to hold three data items in a formatted structure. I need to inspect this field for data entry errors. One of the most common errors is the failure to include one or more spaces to separate the individual data items.

I have written the test template below. What I expect to see as output is "XY". What I get is "".

Can someone point out my error(s)? Thanks.

<xsl:template match="/">
  <xsl:variable name="position-code-candidate">
    <xsl:analyze-string select="'XY02/28/2007 L'" regex="^\w+">
      <xsl:matching-substring>
        <xsl:value-of select="regex-group(1)" />
      </xsl:matching-substring>
    </xsl:analyze-string>
  </xsl:variable>
  <xsl:value-of select="$position-code-candidate" />
</xsl:template>

If you are using regex-group() then you need to specify a group in
your regex using brackets ( ) , just using . if you dont have any
groups.

Also, I'm not sure why you expect "XY" using that regex - you should
expect "XY02"

cheers
andrew