[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Generating a unique listing of elements from multi
Your input wasn't well formed but after fixing that, i think this does what you want. Th e"uniqueness" aspect is automatic given xpath1's node set semantics as sets never have repeated values. <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:key name="c" match="country" use="@id"/> <xsl:key name="cg" match="countryGroup" use="@groupID"/> <xsl:template match="data"> <xsl:apply-templates select="businesses/business"/> </xsl:template> <xsl:template match="business"> <xsl:text> </xsl:text> <xsl:value-of select="name"/> <xsl:text>: </xsl:text> <xsl:for-each select="key('c',key('cg',countryGroup/@included)/country/@included)"> <xsl:value-of select="."/> <xsl:text> </xsl:text> </xsl:for-each> </xsl:template> </xsl:stylesheet> $ saxon gm.xml gm.xsl <?xml version="1.0" encoding="utf-8"?> Acme: United States Mexico Another Acme: Canada Mexico David oops I just use saxon on the command line, silly me:-)
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