[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: new bie question " opening child XML files fails"
Hi Spencer, that does works, but somehow it gives me another problem, my XSL script opens only the first child xml file, and ignore the rests. here is my revised xsl script. " <xsl:variable name="subdir" select="document('index.xml')/protest/package/name"/> <xsl:for-each select="document(concat(document('index.xml')/protest/package/name, '.xml'))/suites/suite/test"> ... </xsl:for-each> " any comments ? cji --- Spencer Tickner <spencertickner@xxxxxxxxx> wrote: > Try > > concat(document('index.xml')/protest/package/name, > '.xml') > > Spencer > > On 12/4/06, chun ji <cji_work@xxxxxxxxx> wrote: > > I have an index.xml file, which reads as: > > " > > -<?xml version="1.0" encoding="ISO-8859-1" ?> > > -<?xml-stylesheet href="rules.xsl" > type="text/xsl"?> > > -<protest> > > -<package> > > -<name>billing</name> > > -</package> > > -<package> > > -<name>timecard</name> > > -</package> > > -</protest> > > ". > > There is a group of child xml files that > associated > > with each "/protest/package/name", such as > > "billing.xml", "timecard.xml". > > > > Now I have soming in my XSL file that tries to > open > > all these CHILD xml files, > > " > > <xsl:for-each > > > select="document(document('index.xml')/protest/package/name)"> > > > > </xsl:for-each> > > " > > which fails, because I did not give ".xml" for > each > > child xml. > > > > Does someone know the format to do it ? > > > > > > thanks a lot > > > > > > cji > > > > > > > > > ____________________________________________________________________________________ > > Yahoo! Music Unlimited > > Access over 1 million songs. > > http://music.yahoo.com/unlimited > > ____________________________________________________________________________________ Cheap talk? Check out Yahoo! Messenger's low PC-to-Phone call rates. http://voice.yahoo.com
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