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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: Fwd: Multiple OR Expression across a node-set
 If the document can contain only a specified subset of "id" values, then you are making far too much of this. Consider these templates:
<xsl:template match="/">
<xsl:apply-templates />
</xsl:template>
<xsl:template match="root">
<xsl:apply-templates select="view[id='foo']" />
<xsl:apply-templates select="view[id='bar']" />
<xsl:apply-templates select="view[id = 'bar_archive']"/>
<xsl:apply-templates select="view[id = 'foo_archive']"/>
</xsl:template>
We have a specific order for the output, no matter what the order of the input, and the fact that a specific template rule may not match an element in the input doc has no effect on the output.
If I have misunderstood your problem, please re-state it.
--
Charles Knell
cknell@xxxxxxxxxx - email
-----Original Message-----
From: Spencer Tickner <spencertickner@xxxxxxxxx>
Sent: Wed, 29 Nov 2006 11:19:20 -0800
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Fwd: Multiple OR Expression across a node-set
My Sincerest apologizes, I accidentally sent this to the xml list.
Hi List,
Thanks in advance for the help. I think I left my brain in Cuba, and
cannot seem to figure out this fairly straight forward problem (well
that and secretly hoping someone has a more elegant way of doing
this).
So I have a generated XML
<root>
<view>
<id>foo</id>
<name>foo</name>
</view>
<view>
<id>bar_archive</id>
<name>Bar Archive</name>
</view>
<view>
<id>bar</id>
<name>bar</name>
</view>
<view>
<id>foo_archive</id>
<name>Foo Archive</name>
</view>
</root>
Issue comes from the fact that every time I get this XML file, the
<view>s are in different, random order. I need them in a specific
order every time. Along with this, sometimes a <view> exists, and
sometimes it doesn't which should be reflected in the output. So far
my XSL looks something like this (I've marked where my if statement is
failing):
<?xml version='1.0'?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<html>
<body>
<!-- This if statement fails (Value of expression cannot be converted
to a node-set in expression) -->
<xsl:if test="root//view/id = 'foo' | root//view/id = 'bar'">
<p>Here are the foo bars</p>
<ul>
<xsl:apply-templates select="root//view[id='bar']"/>
<xsl:apply-templates select="root//view[id='foo']"/>
</ul>
</xsl:if>
<xsl:if test="contains(root//view/id, 'archive')">
<p>Here are archive foo bars</p>
<blockquote>
<xsl:apply-templates select="root//view[id = 'bar_archive']"/>
<xsl:apply-templates select="root//view[id = 'foo_archive']"/>
</blockquote>
</xsl:if>
</body>
</html>
</xsl:template>
<xsl:template match="view" priority="5">
<li><xsl:value-of select="name"/></li>
</xsl:template>
<xsl:template match="view[contains(id, 'archive')]" priority="10">
<p><xsl:value-of select="name"/></p>
</xsl:template>
</xsl:stylesheet>
Any thoughts would be greatly appreciated. (PS - I am stuck with 1.0)
Thanks you,
Spencer Tickner
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