[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] get the current xml file name
hi
this is my first (xslt-beginner) question to this list, hoping my question is not been answered 1 mio times. i was searching in the archive to avoid this. :-) i'm looking for a function that helps me to read and process several .xml files by document(). the problem is that when i say document('nextfile.xml') the document() function tries to read the xml file in the path of the current xslt (!) file. and that's not working for me. so i want to redirect the document() function to the path of the directory of the current .xml file. how can i do that? document-uri(/) reports the whole (!) uri of the current xml file. that includes the path i'm looking for, like file:/C:/somewhere/anywhere/whereami/myfile.xml and that's fine. but how can i now cut off 'myfile.xml' when 'myfile.xml' is always changing and i have no idea of this filename in the xslt and replace it with 'nexfile.xml'? i thought to find a function to get the current xml file name to be able to extract that file from the uri-path-string. but i could not find anything about this. also trying to find a function to find the last '/' in a string and extracting from that with substring-after (). uahh. i hope to find help here. any hint is very appreciated! from switzerland frank
|
PURCHASE STYLUS STUDIO ONLINE TODAY!Purchasing Stylus Studio from our online shop is Easy, Secure and Value Priced! Download The World's Best XML IDE!Accelerate XML development with our award-winning XML IDE - Download a free trial today! Subscribe in XML format
|