[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Only first rows (after the sort)
Hi Dennis, If you solve this problem using Muenchian method (as explained by Wendell), it'll be very efficient. But here is a solution, which is not efficient as the Muenchian method, but this is probably how a layman would think to solve this problem. The logic is quite simple, and only needs one to know how preceding-sibling axis works. <?xml version="1.0"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="html" indent="yes" /> <xsl:template match="/examples"> <html> <head> <title/> </head> <body> <table> <tr> <th>Catagory</th> <th>Year</th> </tr> <xsl:for-each select="example[not(concat(category, year) = concat(preceding-sibling::example/category, preceding-sibling::example/year))]"> <xsl:sort select="category" /> <xsl:sort select="year" data-type="number" /> <tr> <td><xsl:value-of select="category" /></td> <td><xsl:value-of select="year" /></td> </tr> </xsl:for-each> </table> </body> </html> </xsl:template> </xsl:stylesheet> This when applied to XML: <examples> <example> <category>XML</category> <year>2005</year> </example> <example> <category>XSL</category> <year>2005</year> </example> <example> <category>XSL</category> <year>2006</year> </example> <example> <category>XML</category> <year>2005</year> </example> </examples> Produces output: <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> <title></title> </head> <body> <table> <tr> <th>Catagory</th> <th>Year</th> </tr> <tr> <td>XML</td> <td>2005</td> </tr> <tr> <td>XSL</td> <td>2005</td> </tr> <tr> <td>XSL</td> <td>2006</td> </tr> </table> </body> </html> On 8/15/06, Stinissen, Dennis <D.Stinissen@xxxxxxxxx> wrote: Hi,
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