[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Reordering elements
Chad Chelius wrote:
It depends. I assume you have something like <Root> <Story> some content </Story> <Source> some source stuff </Source> <Story> some more content </Story> <Source> some more source stuff </Source> <Root> with one and only one Source element following a Story element. and you want this transformed into <Root> <Story> some content some source stuff </Story> <Story> some more content some more source stuff </Story> <Root> Then the following should work: <xsl:template match="Story"> <Story> <!-- first copy all original children of the Story element --> <xsl:copy-of select="node()"/> <!-- then copy all children of the following Source element --> <xsl:copy-of select="following-sibling::Source[1]/node()"/> </Story> </xsl:template> <!-- suppress Source elements --> <xsl:template match="Source"/> You'll need to process the Root element, and you may want to apply other methods in order to suppress processing the original Source elements. And beware: the code above is completely untested. J.Pietschmann
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