[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Removing duplicates after list is sorted
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> If your creation dates were in a form that could be compared as numbers you could just do this: <xsl:output indent="yes"/> <xsl:key name="base" match="Document" use="Report/@base"/> <xsl:template match="docs"> <docs> <xsl:for-each select="Document[generate-id()=generate-id(key('base',Report/@base))]"> <xsl:variable name="thisgrp" select="key('base',Report/@base)"/> <xsl:copy-of select="$thisgrp[not(@CREATIONTIME > $thisgrp/@CREATIONTIME)][1] "/> </xsl:for-each> </docs> </xsl:template> </xsl:stylesheet> but since they are not, I think something like this is what you want <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output indent="yes"/> <xsl:key name="base" match="Document" use="Report/@base"/> <xsl:template match="docs"> <docs> <xsl:for-each select="Document[generate-id()=generate-id(key('base',Report/@base))]"> <xsl:for-each select="key('base',Report/@base)"> <xsl:sort select="@CREATIONTIME"/> <xsl:if test="position()=last()"> <xsl:copy-of select="."/> </xsl:if> </xsl:for-each> </xsl:for-each> </docs> </xsl:template> </xsl:stylesheet> $ saxon dup.xml dup.xsl <?xml version="1.0" encoding="utf-8"?> <docs> <Document CREATIONTIME="200605051507"> <Report ID="759d" base="ELS"> <Authorized ASC="2"/> </Report> </Document> <Document CREATIONTIME="200605041506"> <Report ID="759c" base="LAN"> <Authorized ASC="0"/> </Report> </Document> </docs> David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
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