Re: Collecting sibling nodes under groupings

Play the video

Subject: Re: Collecting sibling nodes under groupings
From: "Mark Wilson" <drmark@xxxxxxxxxxxxxxx>
Date: Thu, 12 Jan 2006 20:23:48 -0500

Hello David, Thanks for your help. It worked, almost. I did not quite state my problem correctly. I need to add another layer in the final document. All my authors and titles come out at the same level within each grouped Subject element. That is, if there are two book records in a Subject element group, each book's elements are at the same level as every other book's elements within the Subject element. For an arbitrary group of two books, I get: (stylesheet follows example) ------------------------------ <SubjectList> <Subject>Racing Books <Author>Jones</Author> <Title>Racing with the Wind</Title> <Author>Smith</Author> <Title>Happy Days</Title> </Subject> ....... </SubjectList> -------------------------------- When what I need is: (indentation not needed) ------------------------------- <SubjectList> <Subject>Racing Books <Book> <Author>Jones</Author> <Title>Racing with the Wind</Title> </Book> <Book> <Author>Smith</Author> <Title>Happy Days of Racing</Title> </Book> </Subject> ....... </SubjectList> --------------------------------- or this would be even better: ----------------------- <SubjectList> <SubjectEntry> <Subject>Racing Books</Subject> <Book> <Author>Jones</Author> <Title>Racing with the Wind</Title> </Book> <Book> <Author>Smith</Author> <Title>Happy Days of Racing</Title> </Book> </SubjectEntry> ....... </SubjectList>

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0"> <xsl:template match="/"> <SubjectList> <xsl:for-each-group select="/List/Entry" group-by="Subject"> <Subject> <xsl:value-of select="current-grouping-key()"/> <xsl:copy-of select="current-group()/*[not(self::Subject)]"/> </Subject> </xsl:for-each-group> </SubjectList> </xsl:template> </xsl:stylesheet>

----- Original Message ----- From: "David Carlisle" <davidc@xxxxxxxxx> To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx> Sent: Thursday, January 12, 2006 9:00 AM Subject: Re: Collecting sibling nodes under groupings

More to the point, I want to collect all of the sibling nodes from an
entry

you mean child nodes of the entry here not sibling, something like:


<xsl:for-each-group seelct="entry" group-by="Subject">
<entry>
  <xsl:copy-of select="Subject"/>
  <xsl:copy-of select="current-group()/*[not(self::Subject)]"/>
</entry>
</xsl:for-each>

David

________________________________________________________________________
This e-mail has been scanned for all viruses by Star. The
service is powered by MessageLabs. For more information on a proactive
anti-virus service working around the clock, around the globe, visit:
http://www.star.net.uk
________________________________________________________________________

Current Thread
Re: Collecting sibling nodes under groupings Mark Wilson - 13 Jan 2006 02:12:13 -0000 <= David Carlisle - 13 Jan 2006 09:50:35 -0000 Mark Wilson - 13 Jan 2006 11:37:35 -0000 David Carlisle - 13 Jan 2006 12:55:34 -0000

<- Previous	Index	Next ->
RE: RE: Re: Re: Newbie to XSL, Peter Flynn	Thread	Re: Re: Collecting sibling no, David Carlisle
RE: RE: XPath expression conf, cknell	Date	RE: Re: XPath expression conf, cknell
	Month

PURCHASE STYLUS STUDIO ONLINE TODAY!

Purchasing Stylus Studio from our online shop is Easy, Secure and Value Priced!

Download The World's Best XML IDE!

Accelerate XML development with our award-winning XML IDE - Download a free trial today!

Subscribe in XML format

RSS 2.0
Atom 0.3

XML Editor - Download a 15 Day Free Trial Now >

See What's New in Stylus Studio >

Buy Stylus Studio - XML Editor - Now >