[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: position
position() gives the position of a node in the current node list, which in this case is the set of nodes selected by the apply-templates call, which is a list of length one, because you only selected the last one. xsl:number would probably suit your purpose better. You're not trying to count the number of tags, of course, but the number of elements. Most elements have two tags, a start tag and an end tag. Michael Kay http://www.saxonica.com/ > -----Original Message----- > From: Chandrasekhar A [mailto:chandrashekarrvt@xxxxxxxxx] > Sent: 01 December 2005 06:47 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: position > > Hello, > > I am trying to find number of tags in my xml using XSLT. > The XSLT is > > <?xml version="1.0" encoding="UTF-8"?> > <xsl:stylesheet version="1.0" > xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > xmlns:fo="http://www.w3.org/1999/XSL/Format"> > <xsl:output method="text"/> > <xsl:template match="/"> > <xsl:apply-templates > select="dataroot/ReferenceTaskDb[last()]"/> > </xsl:template> > <xsl:template match="ReferenceTaskDb"> > <result> <xsl:value-of select="position()"/></result> > </xsl:template> > </xsl:stylesheet> > > It is returning 1. What is the wrong here ? > > Thanks and Regards, > Chandu
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