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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] key() returning nodes in undesired order.
 <xsl:key name="all-b" match="/set/y/b" use="reference"/> This part all works fine. However, the problem is when the references refer to them in an order which differs than how they are contained in y. So "key('all-b', /set/x/a/reference)" returns the B nodes I'm after, but not in the order which they are in A. Is there such a way to get them in the order which I desire? Unfortunately, having the xml in the 'correct order' before I process isn't an option, and neither is adding sort criteria for each B so I can sort the node set before I use it. The only way I can think to do it now is individually, like:
<xsl:for-each select="/set/x/a/reference">
<xsl:variable name="x" select="key('all-b', .)"/>
...
</xsl:for-each><set> <x> <a> <reference>reference2</reference> <reference>reference1</reference> </a> </x> <y> <b> <reference>reference1</reference> <c>other data</c> </b> <b> <reference>reference2</reference> <c>other data</c> </b> </y> </set> 
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