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Re: removing nodes according to attibute value

Subject: Re: removing nodes according to attibute value
From: drkm <fgeorges.spam@xxxxxxxxx>
Date: Wed, 2 Nov 2005 00:32:12 +0100
get attibute value node
On 11/1/05, Michael Kay wrote:

> > Michael Kay:

> > > Start with an identity template that copies everything:

> > > <xsl:template match="*">
> > >   <xsl:copy><xsl:copy-of
> > > select="@*"/><xsl:apply-templates/></xsl:copy>
> > > </xsl:template>

> >   Or matching "node()" if you want to copy everything, isn't it?

> >     <xsl:template match="node()">
> >       <xsl:copy>
> >         <xsl:copy-of select="@*"/>
> >         <xsl:apply-templates/>
> >       </xsl:copy>
> >     </xsl:template>

> Your version will copy comments and processing instructions,
> mine won't.

  Yes.  It's what I meant (by "everything").  But you're right, it's
not relevant to the OP problem.

--drkm

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