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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Transforming an XML document where the content isn
 Sorry, I was wrong.
The correct XSLT 1.0 stylesheet is -
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html" indent="yes"/>
<xsl:template match="/root">
<html>
<head>
<title/>
</head>
<body>
<xsl:apply-templates select="header" />
</body>
</html>
</xsl:template>
<xsl:template match="header">
<h1><xsl:value-of select="." /></h1>
<xsl:call-template name="printTextNode">
<xsl:with-param name="nodelist"
select="following-sibling::node()[1] | following-sibling::node()[2]"
/>
</xsl:call-template>
</xsl:template>
<xsl:template name="printTextNode">
<xsl:param name="nodelist" />
<p>
<xsl:for-each select="$nodelist">
<xsl:choose>
<xsl:when test="name() = 'a'">
<xsl:copy-of select="." />
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="." />
</xsl:otherwise>
</xsl:choose>
</xsl:for-each>
</p>
</xsl:template>
</xsl:stylesheet>
Hope this helps,
Regards,
Mukul
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