RE: xsl:variable with hex color values

We centralize the choose logic in an attribute set and then just call that
attribute set from the td tag, replacing a css class on the different rows.
We do this on all of our tables and it works well for us.  Hope this helps.

<xsl:attribute-set name="bg1Tobg2">
		<xsl:attribute name="class">
			<xsl:choose>
				<xsl:when test="position() mod 2 =
0">bg_2</xsl:when>
				<xsl:otherwise>bg_1</xsl:otherwise>
			</xsl:choose>
		</xsl:attribute>
	</xsl:attribute-set>

<!--Your loop logic/apply-template and table here-->
			<xsl:for-each>
					<td
xsl:use-attribute-sets="bg1Tobg2" align="right">
						<xsl:value-of
select="./Program" />
					</td>
			</xsl:for-each>

-----Original Message-----
From: Rolando Isidoro [mailto:rli@xxxxxxxxxx] 
Sent: Friday, May 20, 2005 2:34 PM
To: XSL Mulberrytech
Subject:  xsl:variable with hex color values


Hi, I'm trying implementing a XSL which distinguishes odd and even row 
of a table by using different colors. My solution involves the testing 
of the number or the position, something like this:

<xsl:choose>
    <xsl:when test="position() mod 2">
       <td bgcolor = "...">
           ....
       </td>
    </xsl:when>
    <xsl:otherwise>
       <td bgcolor = "...">
           ....
       </td>
    </xsl:otherwise>
</xsl:choose>

the existing code inside each of the <td>'s differs only in the 
background color, which resolves into big time redundancy. Is there any 
way to assign the color value to a variable and then using it in the 
bgcolor attribute? I've tried using something like <xsl:variable 
name="bg" select="Black"> and then <td bgcolor = "$bg"> but it doesn't 
seem to work. I've tried with hex color values, which is my objective, 
and it didn't work either.

Thanks, Rolando