[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: XPath query syntax
Jon, some variant of this should work. You may also want to use
normalize-space().
<?xml version="1.0" encoding="iso8859-1"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml"/> <xsl:template match="/"> <xsl:for-each select="/textarea/node()[name() != 'br']"> <line><xsl:copy-of select="."/></line> </xsl:for-each> </xsl:template> </xsl:stylesheet> From: jpk <jopaki@xxxxxxxxx> I have source XML: _________________________________________________________________ Dont just search. Find. Check out the new MSN Search! http://search.msn.click-url.com/go/onm00200636ave/direct/01/
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