Cart
|
[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: First attempt at xsl:result-document
 Hi Jay,
Thanks for the response. I did try stripping out the file:/// and I
get a java.lang.RuntimeException: "Resolved URL is malformed". This
may be because I tried to really strip down my code to make my problem
more visible on the list. in truth the variable is something more like
<xsl:variable name="filname"
select=concat('file:///W:/test/testing/b/, $myindex, '_', position(),
'.htm')"/>
On 4/25/05, JBryant@xxxxxxxxx <JBryant@xxxxxxxxx> wrote:
> Hi, Spencer,
>
> When I tried your XML and XSL files (after filling in the necessary
> pieces), I found that I got no output unless I removed the "file:///" part
> of the href value.
>
> Jay Bryant
> Bryant Communication Services
> (presently consulting at Synergistic Solution Technologies)
>
> Spencer Tickner <spencertickner@xxxxxxxxx>
> 04/25/2005 11:59 AM
> Please respond to
> xsl-list@xxxxxxxxxxxxxxxxxxxxxx
>
> To
> xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> cc
>
> Subject
> First attempt at xsl:result-document
>
>
> Hi everyone, and thanks in advance for the help.
>
> I have a magical and wonderful xsl that was doing everything I needed
> it too. Unfortunately as this buisness goes, requirements changed.
> Some of the html documents I was producing were getting too large for
> our website. The decision was made to split the larger ones up by
> part. So after some research I found xsl:result-document. Here is some
> sample xml, my single file xsl transformer and my attempt at
> multi-file transformation.
>
> xml
>
> <act>
> <part>this is a part we will divide a file on</part>
> <section>This is a section</section>
> <clause>This is a clause</clause>
> <part>This is another part, in the new scheme of things, a second
> file</part>
> <section>Yet another section</section>
> </act>
>
> original xsl (works fine)
>
> <xsl:template match="act">
>
> <html>
> <body>
> <xsl:apply-templates mode="tableofcontents"/>
> <xsl:apply-templates mode="content"/>
> </body>
> </html>
>
> </xsl:template>
> <!-- Down here of course I have the templates that apply the styles
> for either mode -->
>
> new xsl (well, not so fine)
>
> <xsl:template match="act">
>
> <xsl:result-document href="file:///toc.html" format="html">
> <html>
> <body>
> <xsl:apply-templates mode="tableofcontents"/>
> </body>
> </html>
> </xsl:result-document>
>
> <xsl:for-each select="part">
> <xsl:variable name="filename" select="concat('file:///', position(),
> '.htm'"/>
> <xsl:result-document href={$filename}" format="html">
> <html>
> <body>
> <xsl:apply-templates mode="content"/>
> </body>
> </html>
> </xsl:result-document>
> </xsl:for-each>
> </xsl:template>
>
> <!-- Exact same templates that apply the styles for either mode as
> original xsl -->
>
> In the new xsl, I get the tableof contents no problem. in terms of
> content I get a number of files (same as the number of parts) with no
> content in them. I realize that the for-each statement probably
> doesn't do what I'm hoping it will do, but I can't quite wrap my mind
> around any other ways of doing this. I would really appreciate any
> suggestions or advice.
>
> Thank you all very much,
>
> Spencer
|
PURCHASE STYLUS STUDIO ONLINE TODAY!Purchasing Stylus Studio from our online shop is Easy, Secure and Value Priced! 
Download The World's Best XML IDE!Accelerate XML development with our award-winning XML IDE - Download a free trial today! Subscribe in XML format
|
