[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: xls:for-each not working
However you want to do it - your select is wrong: You are asking for select="/transaction_detail" - which means nodes that are children of ROOT node() not row. Just use select="transaction_detail" -----Original Message----- From: josh higgins [mailto:doopsterus@xxxxxxxxx] Sent: Friday, April 01, 2005 2:47 PM To: xsl Subject: xls:for-each not working I cannot get my for-each statement to work. Am I doing this incorrectly? I am just wanting to output all of the data in the xml file that has a <transaction_data> tag. Here is my statement and below is the sample xml. I use this to attempt to display my template <xsl:call-template name="detail"/> Please help! Thanks! Josh <xsl:template name="detail"> <xsl:for-each select="/invoice/detail/row"> <fo:block> <xsl:value-of select="/transaction_detail"/> </fo:block> </xsl:for-each> </xsl:template> SAMPLE XML <invoice> <detail> <row> <line_sequence>1</line_sequence> <transaction_detail>Activity for (620) 251-1559</transaction_detail> <format_control>C1</format_control> <group_no>1</group_no> </row> <row> <line_sequence>2</line_sequence> <group_no>1</group_no> </row> <row> <line_sequence>3</line_sequence> <transaction_detail> Transaction Activity</transaction_detail> <format_control>C1</format_control> <group_no>1</group_no> </row> <row> <line_sequence>4</line_sequence> <format_control>U1</format_control> <group_no>1</group_no> </row> <row> <line_sequence>5</line_sequence> <transaction_detail> Description</transaction_detail> <group_no>1</group_no> </row> <row> <line_sequence>6</line_sequence> <transaction_detail> ======================================================================== ====</transaction_detail> <group_no>1</group_no> </row> </detail> </invoice> __________________________________ Do you Yahoo!? Yahoo! Personals - Better first dates. More second dates. http://personals.yahoo.com
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