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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] filtering elements using identity transform
 Hi,
You were right. There was an xmlns in my xhtml input and Iam
surprised nobody saw it because it was there in the xhtml snippet I posted
yesterday.
Anyways, like I said earlier, Iam embedding my xml inside the html as I
have a need to go back and forth between the xml and html format to which I
am transforming the xml. So, I thought I'd write an inverse transform that
will just give me back my xml. But does this mean that the input xhtml
should not be bound to any namespace. I have found that the "xmlns:" in
my slideshow element is what's causing the html to appear in my result.
My xhtml snippet looks like
<html>
<head>
</head>
<body>
<p>
<table>
<tr>
<slideshow author="Yours Truly" title="Sample Slide Show" date
="Date of publication" xmlns="urn:hl7-org/v3">
<td>
</td>
And my stylesheet
<xsl:output method="xml" indent="yes" />
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="table">
<xsl:apply-templates/>
</xsl:template>
<xsl:template match="html">
<xsl:apply-templates/>
</xsl:template>
etc
How do I make this work without having to remove the namespace declaration
in my original xml.
Cheers,
Omprakash.V
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