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XSL:IF and Sort Results

Subject: XSL:IF and Sort Results
From: Jason Trépanier <jtrepanier@xxxxxxxxxxx>
Date: Thu, 10 Mar 2005 11:54:48 -0500
xsl sort results
Im trying to display results based on a keyword which is working just fine.

The problem is that it shows the results found 3 times (the current total number of records),
besides that, everything is working nicely.


Code:

<?xml version="1.0" encoding="ISO-8859-1" ?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html" encoding="ISO-8859-1" indent="yes"/>

<xsl:param name="keyword">none</xsl:param>

<xsl:template match="/">

<xsl:apply-templates/>

</xsl:template>

<xsl:template match="fiches/fiche">
<xsl:for-each select="//fiche">
<xsl:sort order="descending" select="texte/fichetitre"/>
<xsl:if test="texte/*= $keyword">
<table width="100%" border="0" cellspacing="0" cellpadding="0">
<tr>
<td width="*" class="pad">
<xsl:value-of select="texte/fichetitre" />
</td>
<td width="150" align="center" class="pad"><xsl:value-of select="texte/typeheberg" /></td>
<td width="150" align="center" class="pad"><xsl:text>temp text</xsl:text></td>
<td width="100" align="center" class="pad"><xsl:value-of select="region/regionnseo" /></td>
</tr>
</table>
</xsl:if>
</xsl:for-each>
</xsl:template>


</xsl:stylesheet>

Anyone know how to fix this?


thank you in advance
J


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