[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Finding the position of node in foreign node list
Tempore 21:18:31, die 03/03/2005 AD, hinc in
xsl-list@xxxxxxxxxxxxxxxxxxxxxx scripsit Jan Rademan
<jrademan@xxxxxxxxxxx>:
Any ideas how I can find out what the position of the current node is in a Hi, I think you can use 'count()' and 'preceding::' (or 'preceding-sibling::') for that purpose. try: count($B/*[...]/preceding::*) were '...' would be something like 'current() = .' regards, -- Joris Gillis (http://www.ticalc.org/cgi-bin/acct-view.cgi?userid=38041) Veni, vidi, wiki (http://www.wikipedia.org)
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