Re: Sorting network addresses

> ....now do u get what i get?
no I get:


$ saxon ip2.xml ip2.xsl
<?xml version="1.0" encoding="UTF-8"?>
<networks>
<network>
<address>1.1.1.1</address>
</network>
<network>
<address>2.3.1.2</address>
</network>
<network>
<address>170.5.2.4</address>
</network>
</networks>

But I just noticed that you are specifying XSLT2 (although you don't have
any xslt2 specific features) so I'll try with saxon8:

I get same:

$ java -jar ../saxon8/saxon8.jar  ip2.xml ip2.xsl
<?xml version="1.0" encoding="UTF-8"?>
<networks>
<network>
<address>1.1.1.1</address>
</network>
<network>
<address>2.3.1.2</address>
</network>
<network>
<address>170.5.2.4</address>
</network>
</networks>

> To repeat how I did it,
> open the XML document, go to the "XSL/XQuery"

sorry that would mean downloading xmlspy first which is too much:-)

What processor does it use for XSLT2 ?

David

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