[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Get the XML File name in XSL?
I have couple of questions: 1. Is there a way in XSL to get the name of the XML file that it is currently transforming? If yes, how? 2. Is there a way to get to the XML file name if its included in another XML file via entities. Let me give you an example to make it a bit clear: Lets say I have master.xml that includes (via entities) 3 other xml files. I am going to send the master.xml and my XSL file to the transformer to transform it to HTML. Since the master.xml includes all three files, as I am transforming each subfile, I want to get the name of the subfile in XSL. Is that possible? Here are example files: I have master.xml file that looks something like this: ------------------------------------------------- <?xml version="1.0"?> <!DOCTYPE root SYSTEM "xml.dtd" [ <!ENTITY % entFile SYSTEM "xml.ent"> %entFile; ]> <root> &subfile1; &subfile2; &subfile3; </root> My xml.ent file looks like this: ------------------------------------------------- <!ENTITY subfile1 SYSTEM "11111.xml" > <!ENTITY subfile2 SYSTEM "22222.xml" > <!ENTITY subfile3 SYSTEM "33333.xml" > ------------------------------------------------- Thanks for your help. __________________________________________________ Do You Yahoo!? Tired of spam? Yahoo! Mail has the best spam protection around http://mail.yahoo.com
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