Re: <xsl:number> in XPath

> I want both the /menus/menu, the (//menu)[$pos] and their ancestors and first
> children, but i can't do something like
> 
> <xsl:apply-templates select="/menus/menu | (//menu)[$pos]" | (//menu)[$pos]/menu
>  | ancestor:menu[(//menu)[$pos]]/>
> 
> or is there something similar?
Sorry, I slipped an error first time.
<xsl:apply-templates select="/menus/menu | (//menu)[$pos] | (//menu)[$pos]/menu
 | (//menu)[$pos]/ancestor::menu" />



=====
Marian
http://www.utdallas.edu/~mgo031000/


		
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