[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: <xsl:number> in XPath
My webmail is not very reliable, sorry for that. > There is always a current node in XSLT, you can always use an axis in a > select expression. so I don't understand this comment. Yes, there is a current node, but it's the root one, not the one i want the ancestors at the moment of the select. <xsl:template match="/"> <xsl:apply-templates select="/menus/menu | (//menu)[$pos]" /> </xsl:template> I want both the /menus/menu, the (//menu)[$pos] and their ancestors and first children, but i can't do something like <xsl:apply-templates select="/menus/menu | (//menu)[$pos]" | (//menu)[$pos]/menu | ancestor:menu[(//menu)[$pos]]/> or is there something similar? > That does seem to be a direct translation of your English into Xpath, so > presumably this is what you want. There was no XSL expressions after that, maybe you forget it? > why do you need to start walking back up the tree here. That select > selects all ancestor menus that have a parent menu (but not ancestor > menus that don't have a parent menu), the current node and any menu > children of the current node. All this taking as reference the current node, correct? If yes, i think it's that what i want. <menu> <menu> <menu> * <menu> --> this is the (//menu)[$pos] <menu> So in the first select i didn't select the one i marked (*), so i need the ancesters of the (//menu)[$pos] > sorry, as a matter of policy never check off-list examples (I waste > enough time just looking at small inlined examples on the list:-) Puting in words, i have that nested <menu> nodes that i want to expand when i click then. So at first i want to show all the first-level menus, and when i click one of then i want to expand to it's first chidrens and so on. Once agains, thank for your insights. Citando David Carlisle <davidc@xxxxxxxxx>: Citando David Carlisle <davidc@xxxxxxxxx>: > > (your message came out one word per line, I had to reflow it to read it) > > > Just a comment on, > > > > To my understanding i canot use > > the axis in the select xpath because they rely on a context node, wich > > i don't have at the time. > > There is always a current node in XSLT, you can always use an axis in a > select expression. so I don't understand this comment. > > However > > > I want to process all <xxx> nodes that > > are at the 1st level of deepness, plus the <xxx> at absolute position > > number n > > > So i translate this to > > > > <xsl:apply-templates > > select="/menus/menu | (//menu)[$pos]" /> > > That does seem to be a direct translation of your English into Xpath, so > presumably this is what you want. > > But this looks a bit strange: > > > <xsl:for-each > > select="ancestor::menu/menu | self::menu | menu"> > > Given that you already slected all your top level menus and the $pos'th > menu in your first <xsl:apply-templates select="/menus/menu | (//menu)[$pos]" > /> > why do you need to start walking back up the tree here. That select > selects all ancestor menus that have a parent menu (but not ancestor > menus that don't have a parent menu), the current node and any menu > children of the current node. > > If thats what you want, this is the right thing, but it looks strange to > me. > > > > The > > XML: > > http://gti.clientes.gtinformatica.pt/Site/Java/Menus.xml > > sorry, as a matter of policy never check off-list examples (I waste > enough time just looking at small inlined examples on the list:-) > > David > > ________________________________________________________________________ > This e-mail has been scanned for all viruses by Star. The > service is powered by MessageLabs. For more information on a proactive > anti-virus service working around the clock, around the globe, visit: > http://www.star.net.uk > ________________________________________________________________________ > > O SAPO ja esta livre de vmrus com a Panda Software, fique vocj tambim! Clique em: http://antivirus.sapo.pt
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