RE: Problem passing node-set to params (RTF)

The error message I'm getting is:

"XSLT 1.0 Debugging Error: Expression did not evaluate
to a node-set"

I'm using XMLSpy to debug my XSLT, but I'm running my
XSL under Java's XSLT parser which I guess is the
Apache XSLT.  I'm running java version 1.4.2_04.  The
error I'm getting is from XMLSpy.

The definition of local is:

<xsl:variable name="local"
select="../member[@component=$localComponent]"/>

And the definition of localComponent is:

<xsl:variable localComponent select = '1' />

Here is the error I get from Java:

org.apache.xpath.XPathException: Can not convert
#STRING to a NodeList!

local and current() are both showing Node-Set in the
debugger.  It's only after I assign then to parameters
using with-param that they become RTFs.  Oddly enough
the guid and agent are shown as node-sets for
attributes, but the other don't.  I don't know what
the problem is.

Thanks
Charlie

Date: Wed, 17 Nov 2004 04:47:26 -0000
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
From: "Michael Kay" <mike@xxxxxxxxxxxx>
Subject: RE:  Problem passing node-set to params
(RTF)
Message-ID:
<S-UTL01-DCPOPPkLbg70001d508@xxxxxxxxxxxxxxxxxxx>

Nothing in the code you have shown us is creating a
result tree 
fragment,
though it's possible that $local is an RTF, since you
haven't shown us 
its
declaration. 

> After reading the FAQ it said
> that assigning existing variables to parameters
turns
> them into RTF.  But, when I tried replacing them
with
> expressions rather than $var it still ended up a
RTF. 

I'm tempted to ask what the FAQ said before you read
it...

Seriously though, you must have misread it. RTFs are
created only by an
xsl:variable, xsl:param, or xsl:with-param element
that has child
instructions rather than a select attribute.

Also, what exactly was the error message? It's better
to quote it 
literally,
especially if you don't fully understand it.

Michael Kay
http://www.saxonica.com/


		
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