[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: can you select name() of attributes?
Hello again,
If someone else might have the same problem, I just wanted to say that I changed the solution to: .. <xsl:template match="/"> <Output> <xsl:for-each select="$Doc2/@*"> <xsl:copy-of select="."/> <xsl:copy-of select="$Doc1/@*[not(name()!=name(current()))]"/> <!-- <xsl:copy-of select="$Doc1/@*[name()=name(current())]"/>--> </xsl:for-each> <xsl:text>Some text in the output element</xsl:text> </Output> </xsl:template> The old line is commented out. I found that the old one would copy every attribute from $Doc1 if but one attribute of the same name exists in $Doc2. Thanks again. Ragulf Pickaxe :-) _________________________________________________________________ Tired of spam? Get advanced junk mail protection with MSN 8. http://join.msn.com/?page=features/junkmail
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