RE: Return position in for-each

In general, move the "test" condition into a predicate in the select
expression of the xsl:for-each. Change

<xsl:for-each select="x">
  <xsl:if test="y">

to

<xsl:for-each select="x[y]">

In your example it's not quite so easy because you are defining a variable
before the <xsl:if>, and the variable itself accesses the position. I don't
understand your logic well enough at this time of night to suggest a
rewrite.

Incidentally, 

  <xsl:variable name="x"><xsl:value-of select="y"/></xsl:variable>

should in 99.99% of cases be rewritten

  <xsl:variable name="x" select="y"/>

Michael Kay 

> -----Original Message-----
> From: Karl J. Stubsjoen [mailto:karl@xxxxxxxxxxxxxxxxxxxx] 
> Sent: 22 July 2004 23:46
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject:  Return position in for-each
> 
> Hello,
> 
> A disadvantage to an xsl:for-each is that the position() 
> increases by one
> for each step.  so, if an xsl:if test validates the current 
> step and says
> "Yes apply templates for this step", "don't apply templates 
> for this step",
> and you are interested in a positiion which reflects the 
> total number of
> "YES" steps... well you have a problem.  Take into consideration this
> for-each rule:
> 
> <xsl:for-each select="Entry">
> <xsl:variable name="element_name"><xsl:value-of
> select="concat('competitor_name_',position())"/></xsl:variable>
>   <xsl:if 
> test="string($BROWSER_VARS//ELEMENT[@name=$element_name]/.)">
>     <tr>
> 
> 	<!-- [[[ HERE WE ADD A COLUMN THAT HAS AN INCREMENTING 
> NUMBER ]]] -->
>       <td><xsl:value-of select="concat(position(),'.')"/></td>
> 
> 	<!-- [[[ HERE WE GET THE REST OF THE COLUMN DATA ]]] -->
>       <xsl:apply-templates select="Element" mode="PRINTER_FRIENDLY">
>          <xsl:with-param name="position"><xsl:value-of
> select="position()"/></xsl:with-param>
>       </xsl:apply-templates>
>     </tr>
>   </xsl:if>
> </xsl:for-each>
> 
> 
> Is there a work-around, or another way to accomplish an 
> incrementing number
> for the TD?
> 
> Karl