[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: can you select name() of attributes?
> XSL snippets (for the non-desired output): grr it's much easier (in general) if you post a complete stylesheet. <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:variable name="Doc1" select="document('doc1.xml')/Input/I"/> <xsl:variable name="Doc2" select="document('doc2.xml')/A/B"/> <xsl:template match="/"> <Output> <xsl:for-each select="$Doc2/@*"> <xsl:copy-of select="."/> <xsl:copy-of select="$Doc1/@*[name()=name(current())]"/> </xsl:for-each> <xsl:text>Some text in the output element</xsl:text> </Output> </xsl:template> </xsl:stylesheet> $ saxon doc.xsl doc.xsl <?xml version="1.0" encoding="utf-8"?> <Output q="input value" r="default">Some text in the output element</Output> ________________________________________________________________________ This e-mail has been scanned for all viruses by Star Internet. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
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