[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: count the number of descending nodes
At 2004-05-06 15:33 +0200, Dionisio Ruiz de Zarate wrote:
hello i have one xml as this: ... i want to see if above of the no node there is one or more nodes with the name my. i make this: <xsl:for-each select="/root/no"> <xsl:choose> <xsl:when test="'count(my) =1'">ok</xsl:when> You shouldn't have put the test into single quotes ... a working example is below. I hope this helps. ................ Ken T:\>type dionisio.xml <root> <no> <my>w</my> <my>e</my> </no> <no> <my>p</my> </no> </root> T:\>type dionisio.xsl <?xml version="1.0" encoding="iso-8859-1"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:output indent="yes"/> <xsl:output method="text"/> <xsl:template match="/"> <xsl:for-each select="/root/no"> <xsl:choose> <xsl:when test="count(my)=1">ok</xsl:when> <xsl:otherwise>no</xsl:otherwise> </xsl:choose> <xsl:text> </xsl:text> </xsl:for-each> </xsl:template> </xsl:stylesheet> T:\>saxon dionisio.xml dionisio.xsl no ok T:\> -- Public courses: Spring 2004 world tour of hands-on XSL instruction Each week: Monday-Wednesday: XSLT/XPath; Thursday-Friday: XSL-FO Hong Kong May 17-21; Bremen May 24-28; Birmingham June 14-18 World-wide on-site corporate, govt. & user group XML/XSL training. G. Ken Holman mailto:gkholman@xxxxxxxxxxxxxxxxxxxx Crane Softwrights Ltd. http://www.CraneSoftwrights.com/s/ Box 266, Kars, Ontario CANADA K0A-2E0 +1(613)489-0999 (F:-0995) Male Breast Cancer Awareness http://www.CraneSoftwrights.com/s/bc Legal business disclaimers: http://www.CraneSoftwrights.com/legal
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