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Re: count the number of descending nodes

Subject: Re: count the number of descending nodes
From: "G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx>
Date: Thu, 06 May 2004 10:06:07 -0400
xsl count
At 2004-05-06 15:33 +0200, Dionisio Ruiz de Zarate wrote:
hello
i have one xml as this:
...
i want to see if above of the no node there is one or more nodes with the
name my.
i make this:
<xsl:for-each select="/root/no">
<xsl:choose>
<xsl:when test="'count(my) =1'">ok</xsl:when>

You shouldn't have put the test into single quotes ... a working example is below.


I hope this helps.

................ Ken

T:\>type dionisio.xml
<root>
 <no>
  <my>w</my>
  <my>e</my>
 </no>
 <no>
  <my>p</my>
 </no>
</root>

T:\>type dionisio.xsl
<?xml version="1.0" encoding="iso-8859-1"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
                version="1.0">

<xsl:output indent="yes"/>
<xsl:output method="text"/>

<xsl:template match="/">
  <xsl:for-each select="/root/no">
    <xsl:choose>
      <xsl:when test="count(my)=1">ok</xsl:when>
      <xsl:otherwise>no</xsl:otherwise>
    </xsl:choose>
    <xsl:text>
</xsl:text>
  </xsl:for-each>
</xsl:template>

</xsl:stylesheet>
T:\>saxon dionisio.xml dionisio.xsl
no
ok

T:\>

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