[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: outputting <? in resulting XML
Thank you all. It worked like a charm. -----Original Message----- From: Josh Canfield [mailto:Josh.Canfield@xxxxxxxxxxxx] Sent: Wednesday, April 21, 2004 12:15 PM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: RE: outputting <? in resulting XML Use the processing instruction element: http://www.w3.org/TR/xslt#section-Creating-Processing-Instructions <xsl:processing-instruction name="mso-application">progid="Excel.Sheet"</xsl:processing-instruction> Check out the Mulberry quickref, it contains a quick list of available elements. http://www.mulberrytech.com/quickref/XSLTquickref.pdf Then if you want to know more about an element, try the XSLT spec: http://www.w3.org/TR/xslt Josh -----Original Message----- From: Jasthi, Siva R. [mailto:siva.jasthi@xxxxxxxxxx] Sent: Wednesday, April 21, 2004 10:00 AM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: outputting <? in resulting XML Hi - I am trying to convert a source XML to a resulting XML that confirms to SchemaML (Microsoft Office 2003 XML). I need to have the following line in the resulting XML. <?mso-application progid="Excel.Sheet"?> My stylesheet snippet looks as follows. <xsl:template match="/"> <?mso-application progid="Excel.Sheet" ?> ... .... </xsl:template> However, in the final output, <?mso-application progid="Excel.Sheet" ?> is NOT appearing. Can you pl. let me know how XSLT interprets the <? tag? Thanks - jasthi
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